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The Midpoints of Two Cevians

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area(AMN)
≈
17.57
4area(AMN)
≈
70.27
area(BC'B'C)
≈
70.27
A cevian is a line drawn from a vertex of a triangle to the opposite side.
Let ABC be a triangle and let M and N be the midpoints of the cevians BB' and CC'. Then the area of the quadrilateral BC'B'C is 4 times the area of AMN.
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