WOLFRAM|DEMONSTRATIONS PROJECT

Perpendiculars from a Point on the Line between the Endpoints of the Angle Bisectors

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P
PA''
≈
1.57
PB''
≈
2.93
PQ
≈
4.50
PA''
+
PB''
≈
4.50
Let ABC be a triangle. Let AA' and BB' bisect the angles CAB and ABC. Let P be a point on A'B' and PQ be perpendicular to AB. Let PB'' and PA'' be perpendicular to AC and BC. Then PQ = PA'' + PB''.