t
y
p
e
o
f
f
o
r
m
u
l
a
c
l
o
s
e
d
o
p
e
n
s
u
b
d
i
v
i
s
i
o
n
s
1
2
3
4
5
e
n
d
p
o
i
n
t
b
1
1
π
6
N
e
w
t
o
n
-
C
o
t
e
s
f
o
r
m
u
l
a
:
3
8
h
(
f
(
x
0
)
+
3
f
(
x
1
)
+
3
f
(
x
2
)
+
f
(
x
3
)
)
i
n
t
e
g
r
a
l
:
a
p
p
r
o
x
i
m
a
t
e
d
v
a
l
u
e
=
0
.
2
8
1
2
9
5
a
c
t
u
a
l
v
a
l
u
e
=
0
.
1
3
3
9
7
5
e
r
r
o
r
=
0
.
1
4
7
3
2