Evaluate
a
k
=
1
2
+
1
k
join
n
ϵ
prospective
limit
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
●
0
.
55
0
.
60
0
.
65
0
.
70
a
k
limit
=
0
.
5
