WOLFRAM NOTEBOOK

WOLFRAM|DEMONSTRATIONS PROJECT

Conduction through a Composite Wall

conductivity of end wall (W/m/K)
fiberglass (0.04)
brick (1.4)
lead (35)
glass thickness (cm)
1.4
cement thickness (cm)
1.6
stainless steel thickness (cm)
2.3
left wall temp (°C)
80
This Demonstration calculates temperature profiles for steady-state conduction through multiple walls in series. The physical situation is a composite wall with the end temperatures fixed (as a result of convection or radiation). Therefore, the flux is equal to the difference of the two end temperatures over the resistance. The total thickness of the walls is 10 cm. You can vary the temperature of the left wall; the temperature of the right wall is fixed at 45 °C. You can vary the thicknesses of the first three walls and the conductivity of the fourth wall. The heat flux, which is the same through each wall, is calculated, and the temperature distribution through each wall is plotted.
Wolfram Cloud

You are using a browser not supported by the Wolfram Cloud

Supported browsers include recent versions of Chrome, Edge, Firefox and Safari.


I understand and wish to continue anyway »

You are using a browser not supported by the Wolfram Cloud. Supported browsers include recent versions of Chrome, Edge, Firefox and Safari.