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Ceva's Theorem

​
AB'
≈
4.78
BC'
≈
9.49
CA'
≈
7.63
AB'
×
BC'
×
CA'
≈
346.57
AC'
≈
5.39
BA'
≈
5.08
CB'
≈
12.65
AC'
×
BA'
×
CB'
≈
346.57
Let P be a point inside the triangle ABC. Draw lines from A, B and C through P to the points A', B', and C' on the opposite sides. Then AB'×BC'×CA' = AC'×BA'×CB'.
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