l
e
n
g
t
h
L
1
0
b
r
e
a
d
t
h
B
4
.
3
a
r
e
a
o
f
r
e
c
t
a
n
g
l
e
=
L
×
B
=
1
0
×
4
.
3
=
4
3
.
p
e
r
i
m
e
t
e
r
o
f
r
e
c
t
a
n
g
l
e
=
2
(
L
+
B
)
=
2
(
1
0
+
4
.
3
)
=
2
8
.
6
d
i
a
g
o
n
a
l
l
e
n
g
t
h
=
2
L
+
2
B
=
2
1
0
+
2
4
.
3
=
1
0
.
9