WOLFRAM
|
DEMONSTRATIONS PROJECT
Binomial Theorem
e
x
p
o
n
e
n
t
3
0
(
x
+
1
)
=
1
+
3
0
x
+
4
3
5
2
x
+
4
0
6
0
3
x
+
2
7
4
0
5
4
x
+
1
4
2
5
0
6
5
x
+
5
9
3
7
7
5
6
x
+
2
0
3
5
8
0
0
7
x
+
5
8
5
2
9
2
5
8
x
+
1
4
3
0
7
1
5
0
9
x
+
3
0
0
4
5
0
1
5
1
0
x
+
5
4
6
2
7
3
0
0
1
1
x
+
8
6
4
9
3
2
2
5
1
2
x
+
1
1
9
7
5
9
8
5
0
1
3
x
+
1
4
5
4
2
2
6
7
5
1
4
x
+
1
5
5
1
1
7
5
2
0
1
5
x
+
1
4
5
4
2
2
6
7
5
1
6
x
+
1
1
9
7
5
9
8
5
0
1
7
x
+
8
6
4
9
3
2
2
5
1
8
x
+
5
4
6
2
7
3
0
0
1
9
x
+
3
0
0
4
5
0
1
5
2
0
x
+
1
4
3
0
7
1
5
0
2
1
x
+
5
8
5
2
9
2
5
2
2
x
+
2
0
3
5
8
0
0
2
3
x
+
5
9
3
7
7
5
2
4
x
+
1
4
2
5
0
6
2
5
x
+
2
7
4
0
5
2
6
x
+
4
0
6
0
2
7
x
+
4
3
5
2
8
x
+
3
0
2
9
x
+
3
0
x
E
x
p
a
n
d
i
n
g
a
s
i
m
p
l
e
p
o
l
y
n
o
m
i
a
l
.
