WOLFRAM|DEMONSTRATIONS PROJECT

Angle Bisector Theorem

​
BD
≈
2.85
AC
≈
7.80
AB
≈
6.62
DC
≈
3.36
BD
×
AC
≈
22.25
AB
×
DC
≈
22.25
∠BAD
≈
25.15°
∠CAD
≈
25.15°
Let ABC be a triangle. Let AD bisect
∠
BAC. Then BD×AC = AB×DC.