# 24b. Construct a Triangle Given the Length of the Altitude to the Base, the Difference of Base Angles and the Sum of the Lengths of the Other Sides

24b. Construct a Triangle Given the Length of the Altitude to the Base, the Difference of Base Angles and the Sum of the Lengths of the Other Sides

This Demonstration uses a conchoid to construct a triangle given the difference of the base angles and , the length of the altitude from the base and the sum of the lengths of the legs.

ABC

δ

β

α

h

C

s

The conchoid, shown in red, determined by and , intersects the straight line through that forms an angle with the horizontal line through in the points and . The triangle is the solution.

DC=

h

C

DF=s

E

δ

D

A

B

ABC