24b. Construct a Triangle Given the Length of the Altitude to the Base, the Difference of Base Angles and the Sum of the Lengths of the Other Sides
24b. Construct a Triangle Given the Length of the Altitude to the Base, the Difference of Base Angles and the Sum of the Lengths of the Other Sides
This Demonstration uses a conchoid to construct a triangle given the difference of the base angles and , the length of the altitude from the base and the sum of the lengths of the legs.
ABC
δ
β
α
h
C
s
The conchoid, shown in red, determined by and , intersects the straight line through that forms an angle with the horizontal line through in the points and . The triangle is the solution.
DC=
h
C
DF=s
E
δ
D
A
B
ABC