Solution SG 48
Solution SG 48
2002 December 02
Isaac Abraham
Isaac Abraham
What is the output voltage v(out) of this simple amplifier?
You are given the VCE, IC of the transistor.
VCE (V) IC (A) 1.5 1.02E-031.25 1.01E-031.1 1.01E-031 1.01E-030.8 1.01E-030.7 1.01E-030.5 1.01E-030.25 9.87E-040.15 8.10E-040.125 6.28E-040.1 3.95E-040.08 2.33E-040.07 1.67E-040.06 1.17E-040.05 7.70E-050.04 4.70E-050.03 2.50E-050.02 1.00E-05
The output voltage is the intersection of the I-V curve of the two components that control net out. The intersection can be determined graphically.
In[]:=
XTORIV={{1.5,1.0210^-3},{1.25,1.0110^-3},{1.1,1.0110^-3},{1.0,1.0110^-3},{0.8,1.0110^-3},{0.7,1.0110^-3},{0.5,1.0110^-3},{0.25,9.8710^-4},{0.15,8.110^-4},{0.125,6.2810^-4},{0.1,3.9510^-4},{0.08,2.3310^-4},{0.07,1.6710^-4},{0.06,1.1710^-4},{0.05,7.710^-5},{0.04,4.710^-5},{0.03,2.510^-5},{0.02,1.10^-5}}
Out[]=
{{1.5,0.00102},{1.25,0.00101},{1.1,0.00101},{1.,0.00101},{0.8,0.00101},{0.7,0.00101},{0.5,0.00101},{0.25,0.000987},{0.15,0.00081},{0.125,0.000628},{0.1,0.000395},{0.08,0.000233},{0.07,0.000167},{0.06,0.000117},{0.05,0.000077},{0.04,0.000047},{0.03,0.000025},{0.02,0.00001}}
In[]:=
RESIV={{0,1.5/2200},{1.5,0}}
Out[]=
{{0,0.000681818},{1.5,0}}
In[]:=
ListPlot[Tooltip@{XTORIV,RESIV},JoinedTrue,FrameTrue,FrameStyle16,FrameLabel{"v(out), V","i, A"},GridLinesAutomatic]
Out[]=
You can hover your mouse over the visual intersection point to see that it is about 125 mV.