pp=pH2->
1-x
3
,pI2->
1-x
3
,pHI->
1+2x
3
​​Solve[pHI==5pH2/.pp,x]​​ppf=pp/.x->
4
7
​​Kp=
2
pHI
pH2pI2
/.ppf​​Solve[-8.3145TLog[25]==-8370-17.65T,T]
Out[]=
pH2
1-x
3
,pI2
1-x
3
,pHI
1
3
(1+2x)
Out[]=
x
4
7

Out[]=
pH2
1
7
,pI2
1
7
,pHI
5
7

Out[]=
25
Solve
:
1006.68
Log-0.1196951642027181-
1.000000000000000
2
Plus[2]
-
4.000000000000000x
2
Plus[2]
-
4.000000000000000
2
x
2
Plus[2]

is not a valid variable.
In[]:=
T=
1006.68
Log-0.1196951642027181-
1.000000000000000
2
(1.000000000000000-1.000000000000000x)
-
4.000000000000000x
2
(1.000000000000000-1.000000000000000x)
-
4.000000000000000
2
x
2
(1.000000000000000-1.000000000000000x)

In[]:=
Simplify[T]
In[]:=
{25==E^((-0.120272*(-8370-17.65*T))/T),T}​​
Out[]=
25
-0.000119474-8370-
17767.9
Log-0.1196951642027181-
1.000000000000000
2
(1.000000000000000-1.000000000000000x)
-
4.000000000000000x
2
(1.000000000000000-1.000000000000000x)
-
4.000000000000000
2
x
2
(1.000000000000000-1.000000000000000x)

0.1196951642027181
-0.000119474-8370-
17767.9
Log-0.1196951642027181-
1.000000000000000
2
(1.000000000000000-1.000000000000000x)
-
4.000000000000000x
2
(1.000000000000000-1.000000000000000x)
-
4.000000000000000
2
x
2
(1.000000000000000-1.000000000000000x)

1.000000000000000
2
(1.000000000000000-1.000000000000000x)
+
4.000000000000000x
2
(1.000000000000000-1.000000000000000x)
+
4.000000000000000
2
x
2
(1.000000000000000-1.000000000000000x)
,
1006.68
Log-0.1196951642027181-
1.000000000000000
2
(1.000000000000000-1.000000000000000x)
-
4.000000000000000x
2
(1.000000000000000-1.000000000000000x)
-
4.000000000000000
2
x
2
(1.000000000000000-1.000000000000000x)

