GeometricLocusEllipses::usage="Find and identify the equation of the geometric locus of the center of a circle that remains tangent to the circles + - 4y - 12 = 0 and + = 1 (Two solutions). These are two ellipses: 100 + 84- 168 y - 441 = 0 and 36 + 20 - 40 y - 25 = 0. The animation explains how they are formed. References: Lehmann, Charles H. Geometría Analítica. Ed. Limusa: p.186, 2003; Personal. ";
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Case 1:
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10++4y29;Expand==
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(29-4y)
400+100-400y+100841-232y+16;100+84-168y-441==0;
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Case 2:
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6++4y13;Expand==
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(13-4y)
144+36-144y+36169-104y+16;36+20-40y-25==0;
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Animation:
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Animateg1=PointSin[θ],Cos[θ]+1/.θθ1;g2=PointSin[θ],Cos[θ]+1/.θθ1;g3=Circle[{0,2},4];g4=Circle[{0,0},1];g5=ParametricPlotSin[θ],Cos[θ]+1,Sin[θ],Cos[θ]+1,{θ,0,θ1},PlotStyleDashed,ColorFunction->"Aquamarine";xr=Sin[θ1];yr=Cos[θ1]+1;rr=+-1;xp=Sin[θ1];yp=Cos[θ1]+1;rp=++1;g6=Circle[{xr,yr},rr];g7=Circle[{xp,yp},rp];Show[{g5,Graphics[{Red,Thick,PointSize[0.018],g1}],Graphics[{Purple,Thick,PointSize[0.018],g2}],Graphics[{Black,g3}],Graphics[{Black,g4}],Graphics[{Red,g6}],Graphics[{Purple,g7}]},AxesTrue,AxesOrigin{0,0},BoxRatiosAutomatic,PlotRangeAll,PerformanceGoal"Quality"],{θ1,0.01,2π,0.1},AnimationRunningFalse
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