Laminar Flow Friction Factor in Elliptical Ducts
Authors: Housam Binous and Ahmed Bellagi
Laminar Flow Friction Factor in Elliptical Ducts
Authors: Housam Binous and Ahmed Bellagi
Authors: Housam Binous and Ahmed Bellagi
The friction factors for elliptical ducts at low Reynolds numbers are given by where depends on a/b as follows (see Ref. 1): with = and where P is the perimeter of the elliptical duct. If the ellipse is defined by: +=1 and , then exact perimeter of an ellipse is given by: where: E(m) is the complete elliptic integral of the second kind and e is the eccentricity defined as: .Some numerical values of are given in Table 2 of Ref. 1 (see below). Here, we reproduce this Table but for the Darcy friction factor.In addition, we provide a plot of A versus a/b.References:[1] Y. S. Muzychka and M. M. Yovanovich, Laminar flow friction and heat transfer in non-circular ducts and channels (Part 1: Hydrodynamic problem), Compact Heat Exchangers, A Festschrift on the 60th Birthday of Ramesh K. Shah, Grenoble, France, August 24, 2002.
f=
A
Re
Dh
A
A=f=
Re
Dh
8(+)
2
a
2
b
2
Dh
2
a
2
b
Re
Dh
ρuDh
η
Dh=4π
ab
P
2
x
2
a
2
y
2
b
b>=a
P=4bE()
2
e
e=
1-
2
a
2
b
f*/4
Re
Dh
In[]:=
(*Eccentricity*)e=Sqrt[1-(a^2/b^2)];(*Ellipseperimeterusingellipticintegral*)P=4bEllipticE[e^2]//N;(*Hydraulicdiameter*)Dh=4Piab/P//N;(*Darcyfrictionfactor*)A=(8Dh^2)*((a^2+b^2)/(a^2b^2))//N;
In[]:=
dataTable=Table[{i,A/.a->bi},{i,0.05,1,0.05}];
In[]:=
Grid[Prepend[dataTable,{"Radius ratio b/a","f*Re_Dh or A"}],Frame->All,Background->{None,{Lighter[Blend[{Blue,Red}],.3],{Lighter[Blend[{Blue,Darker@Red}],.8],Lighter[Red,.9]}}},ItemSize->{8.4,2.0},Frame->Darker[Gray,.6],ItemStyle->14,Spacings->{Automatic,.8}]
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Radius ratio b/a | f*Re_Dh or A |
0.05 | 78.391 |
0.1 | 77.2555 |
0.15 | 75.8741 |
0.2 | 74.4096 |
0.25 | 72.9598 |
0.3 | 71.5841 |
0.35 | 70.317 |
0.4 | 69.1762 |
0.45 | 68.1685 |
0.5 | 67.2932 |
0.55 | 66.545 |
0.6 | 65.9157 |
0.65 | 65.3959 |
0.7 | 64.9754 |
0.75 | 64.644 |
0.8 | 64.3917 |
0.85 | 64.2094 |
0.9 | 64.0885 |
0.95 | 64.021 |
1. | 64. |
In[]:=
data=Table[{i,A/.a->bi},{i,0.001,1,0.001}];
In[]:=
ListPlot[data,PlotRange->{{0.0,1},{60,80}},Frame->True,GridLines->Automatic,PlotStyle->Darker@Red,AspectRatio->1,Joined->True,FrameLabel->{Style["a/b",16],Style["A",16]}]
Out[]=