If: then: [x,t]=0 and [x,t]=0
b[x,t]->
c
4
(1,0)
b
(0,1)
b
In[]:=
-+0/.[x,t]->0,-==0/.b[x,t]->,0/.[x,t]->0
2[t]
′
h
2
c
2h[t][x,t]
(1,0)
b
2
c
(1,0)
b
h[t]
4
b[x,t]h[t]
2
c
c
4
2Xi[2][t][x,t]
(0,1)
b
2
c
(0,1)
b
Out[]=
-0,-0,True
2[t]
′
h
2
c
h[t]
4
h[t]
4c
In[]:=
Solve-0,h[t]
h[t]
4
h[t]
4c
Out[]=
{{h[t]0}}
In[]:=
DSolve-0,h[t],t
2[t]
′
h
2
c
Out[]=
{{h[t]}}
1
(*----------------------------------------------------------------------------------------------------------------------------*)
DSolve-+2[x,t]==0,-+0,-==0,{Xi[2][t],h[t],f[x,t],b[x,t]},{x,t}(*Syntaxiswrong!!Imeanthis:"{Xi[2][t],h[t],f[x,t],b[x,t]},{x,t}"*)(*Inthisexampleyouhave3equationsbut4unknowns?*)
2[t][x,t]
′
Xi[2]
(1,0)
b
2
c
2[t]
′′
Xi[2]
2
c
(1,0)
f
2[t]
′
h
2
c
2h[t][x,t]
(1,0)
b
2
c
h[t]
4
b[x,t]h[t]
2
c