PedalSurfaceofaLevelSurface::usage="Given the function f[x, y, z] = x y z, obtain for the level surface x y z = 1 its corresponding pedal surface with respect to the origin.Rederences: Problemas de Geometría Analítica y Diferencial, Ubaldo Usunáriz Balanzategui, Ignacio Usunáriz Sala, Prob.- H5; Personal";
Development:
Equation of the tangent plane at the point P (α, β, γ):
f[x_,y_,z_]:=xyz-1;[x_,y_,z_]=D[f[x,y,z],x];[x_,y_,z_]=D[f[x,y,z],y];[x_,y_,z_]=D[f[x,y,z],z];(x-α)[x,y,z]+(y-β)[x,y,z]+(z-γ)[x,y,z]==0
f
x
f
y
f
z
f
x
f
y
f
z
yz(x-α)+xz(y-β)+xy(z-γ)0;1-yzα+1-xzβ+1-xyγ==0;βγx+αγy+αβz-3==0;
Equation of the normal line:
x
βγ
y
αγ
z
αβ
Parametric equations of the Pedal Surface:
Solve====,βγx+αγy+αβz-3==0,{x,y,z}
x
βγ
y
αγ
z
αβ
x++,y++,z++;
3βγ
2
α
2
β
2
α
2
γ
2
β
2
γ
3αγ
2
α
2
β
2
α
2
γ
2
β
2
γ
3αβ
2
α
2
β
2
α
2
γ
2
β
2
γ
Cartesian equation of the Pedal Surface:
Solvex==++,y==++,z==++,{α,β,γ}
3βγ
2
α
2
β
2
α
2
γ
2
β
2
γ
3αγ
2
α
2
β
2
α
2
γ
2
β
2
γ
3αβ
2
α
2
β
2
α
2
γ
2
β
2
γ
α+x+x,β,γ,α-+x+x,β-,γ-;
3
y
z
3
x
2
y
2
z
3
xz
y
x(++)
2
x
2
y
2
z
3
xy
z
x(++)
2
x
2
y
2
z
3
y
z
3
x
2
y
2
z
3
xz
y
x(++)
2
x
2
y
2
z
3
xy
z
x(++)
2
x
2
y
2
z
It is fulfilled that α β γ == 1, ==1:
2
α
2
β
2
γ
3yz
3
x
2
y
2
z
3xz
2
x
3
y
2
z
3xy
2
x
2
y
3
z
27
2
x
2
y
2
z
xyz
3
(++)
2
x
2
y
2
z
3
(++)
2
x
2
y
2
z
In[]:=
Manipulatef[x_,y_,z_]:=xyz-1;[x_,y_,z_]:=-27xyz;Show[ContourPlot3D[f[x,y,z]==0,{x,-2,2},{y,-2,2},{z,-2,2},PerformanceGoal"Quality",MeshStyleDirective[AbsoluteThickness[0.5],Opacity[0.2]],ContourStyleOpacity[0.1]],ContourPlot3D[[x,y,z]==0,{x,-2,k1},{y,-2,2},{z,-2,2},PerformanceGoal"Quality",MeshStyleDirective[AbsoluteThickness[0.5],Opacity[0.4]],ContourStyleOpacity[0.6]],Graphics3D[{Black,Ball[{0,0,0},0.06]}],AxesLabel->(Style[#,15,Blue]&/@{"X","Y","Z"}),AxesOrigin{0,0,0},AxesTrue,BoxedFalse,ViewPoint{1.3,-2.4,1.},PlotRangeAll,ImageSize500,BoxRatiosAutomatic],{k1,-2+0.00001,2,0.00001},SaveDefinitionsTrue,ControlPlacementTop
f
p
3
(++)
2
x
2
y
2
z
f
p
Out[]=
We make a cut with the plane x = y on the original surface and we get a curve, then we get its pedal curve:
In[]:=
ζ[t_]:=t,t,;ζ'[t]
1
2
t
1,1,-;
2
3
t
Equation of the orthogonal plane to the tangent line (goes through the origin):
x+y-z==0;x+y-2z==0;
2
3
t
3
t
3
t
Parametric equations of the Pedal Curve:
In[]:=
Solvex+y-2z==0,====,{x,y,z}//FullSimplify
3
t
3
t
x-t
3
t
y-t
3
t
z-
1
2
t
-2
x,y,z;
3t
2+
6
t
3t
2+
6
t
3
4
t
2+
6
t
ζ
11
3t
2+
6
t
3t
2+
6
t
3
4
t
2+
6
t
We make a cut with the plane x = - y on the original surface and we get a curve, then we get its pedal curve:
In[]:=
ζ
1
1
2
t
ζ
1
-1,1,;
2
3
t
3
t
3
t
Parametric equations of the Pedal Curve:
In[]:=
Solvex-y-2z==0,====,{x,y,z}//FullSimplify
3
t
3
t
x+t
3
t
y-t
-
3
t
z+
1
2
t
-2
x-,y,z-;
3t
2+
6
t
3t
2+
6
t
3
4
t
2+
6
t
ζ
22
3t
2+
6
t
3t
2+
6
t
3
4
t
2+
6
t
In[]:=
SwatchLegend[{Black,Red,Blue,DarkGreen},{"Original curves","Pedal curve to the original curve","Tangent line to each original curve","Orthogonal line to each tangent line"}]Manipulateζ[t_]:=t,t,;[t_]:=-t,t,-;[t_]:=,,;[t_]:=-,,-;ℒ[t_]:=ζ[t]+vζ'[t];[t_]:=[t]+v'[t];Show[ParametricPlot3D[ζ[t],{t,-π,π},PlotStyle{Black,Thick}],ParametricPlot3D[[t],{t,-π,π},PlotStyle{Black,Thick}],Graphics3D[{Black,Ball[ζ[k1],0.07]}],Graphics3D[{Black,Ball[[k1],0.07]}],Graphics3D[{Black,Ball[{0,0,0},0.07]}],ParametricPlot3D[[t],{t,-π,π},PlotStyle{Red,Thick},PerformanceGoal->"Quality"],ParametricPlot3D[[t],{t,-π,π},PlotStyle{Red,Thick},PerformanceGoal->"Quality"],Graphics3D[{Red,Ball[[k1],0.07]}],Graphics3D[{Red,Ball[[k1],0.07]}],ParametricPlot3D[ℒ[k1],{v,-π,π},PlotStyle->{Blue,Thick}],ParametricPlot3D[[k1],{v,-π,π},PlotStyle->{Blue,Thick}],Graphics3D[{DarkGreen,Thick,Line[{{0,0,0},[k1]}]}],Graphics3D[{DarkGreen,Thick,Line[{{0,0,0},[k1]}]}],AxesLabel->(Style[#,15,Blue]&/@{"X","Y","Z"}),AxesOrigin{0,0,0},AxesTrue,BoxedFalse,ViewPoint{1.3,-2.4,1.},BoxRatiosAutomatic,PlotRange5,ImageSize900],{k1,-π,π,0.00001},SaveDefinitionsTrue,ControlPlacementTop
1
2
t
ζ
1
1
2
t
ζ
11
3t
2+
6
t
3t
2+
6
t
3
4
t
2+
6
t
ζ
22
3t
2+
6
t
3t
2+
6
t
3
4
t
2+
6
t
ℒ
1
ζ
1
ζ
1
ζ
1
ζ
1
ζ
11
ζ
22
ζ
11
ζ
22
ℒ
1
ζ
11
ζ
22
This clearly explains why the Pedal Surface it’s like above.

