PARTICLE IN CONSTANT POTENTIAL

BY JOHN BAXTER
​
The Hamiltonian Operator

H
for a particle moving in a constant Potential V(x) takes the following form where the Potential V(x)=V does not depend on the Position, x.​​

H
=
2

P
2m
+V(x)
​​Therefore, the Time Dependent Wave Equation becomes…​​

H
|ψ(x,t)〉=iℏ
d
dt
|ψ(x,t)〉
​​​
2

P
2m
|ψ(x,t)〉+V|ψ(x,t)〉=iℏ
d
dt
|ψ(x,t)〉
where
ψ(x,t)=
i(kx-ωt)
e
​​​
-
2
ℏ
2m
2
d
2
dx
i(kx-ωt)
e
+V
i(kx-ωt)
e
=iℏ
d
dt
i(kx-ωt)
e
​​​
ω=
2
ℏk
2m
+
V
ℏ
⟹
E
T
=ℏω=
2
ℏ
2
k
2m
+V
wherek=
p
ℏ
In[]:=
Clear[ℏ]​​ψ[x_,t_]:=
(kx-ωt)

​​GridSimplifySolve-
2
ℏ
2m
∂
{x,2}
ψ[x,t]+Vψ[x,t]ℏ
∂
t
ψ[x,t],ω[[1,1]]/.(x_y_)(xy),"Angular Frequency",{
E
T
ℏω,"Total Energy"},Spacings5,AlignmentLeft
Out[]=
ω
V
ℏ
+
2
k
ℏ
2m
Angular Frequency
E
T
ωℏ
Total Energy
In[]:=
Grid[{{
E
T
Simplify[ℏω/.ToRules[%[[1,1,1]]]],"Total Energy"}},Spacings5,AlignmentLeft]
Out[]=
E
T
V+
2
k
2
ℏ
2m
Total Energy
From the relations above, we generate the animated plot below. 1. Momentum, p: The wave moves at momentum p=ℏk.​ 2. Mass, m: As the mass, m increases, the velocity of the particle decreases to maintain a constant Momentum, k. We see this relation from the equation p=mv. Where lowercase v denotes velocity. 3. Potential Energy, V: The particle moves through a constant Potential Energy Field that opposes the movement of the particle when the Potential Energy, V is positive. 4. Total Energy,
E
T
: As the Potential Energy, V increases, the particle requires a higher Total Energy,
E
T
to maintain it’s Momentum, p.
In[]:=
ManipulateGridPlotRe

p
ℏ
x-ωt

/.ω
V
ℏ
+
2
p
2ℏm
/.ℏ1,{x,0,8},PlotRange1,PlotLabelsPlaced["Re(ψ)",Scaled[.9]],AxesLabel{"x","ψ(x,t)"},PlotLabelColumn[{"Wave Function","in Constant Potential"},AlignmentCenter],BarChartV+
2
p
2m
/.ℏ1,PlotRange{-2,6},PlotLabel"Total Energy
E
T
",ItemSizeFull,{t,0,4π,AnimationRunningTrue},p,
π
4
,
π
8
,π,
π
8
,{{m,1},1,10,.1},{{V,0},-1,1}
Out[]=
​
t
p
m
V