Development:
2
(x-a)
2
y
2
x
2
y
Raising both members squared and developing remains:
-2ax-+=-2r+
2
r
2
a
2
x
2
y
Be a = 3 and r = 5, then:
-6x-16=-10+;3x+8=5+;
2
x
2
y
2
x
2
y
Raising both members squared and developing remains:
-64-48x+16+25=0;
2
x
2
y
The point P is on the line and it must be fullfilled that = , then:
OC
PC
PA
A={3,0};r=5;C1[θ_]:=r{Cos[θ],Sin[θ]};P[θ_,λ_]:=λC1[θ];Solve[Norm[P[θ,λ]-A]==Norm[P[θ,λ]-C1[θ]],λ]
In[]:=
λ;λ=;P[θ]=λC1[θ]
-9+25+25
2
Cos[θ]
2
Sin[θ]
10(-3Cos[θ]+5+5)
2
Cos[θ]
2
Sin[θ]
8
5(5-3Cos[θ])
,;
8Cos[θ]
5-3Cos[θ]
8Sin[θ]
5-3Cos[θ]
Manipulater=5;O1={0,0};A={3,0};P[θ_]:=,;C1[θ_]:=r{Cos[θ],Sin[θ]};d1=Norm[P[θ1]-C1[θ1]];d2=Norm[P[θ1]-A];t=Grid[{{,},{N[d1],N[d2]}},FrameAll,ItemStyle->15,ItemStyle->15];Show[{ContourPlot[y-5Sin[θ1]==-Cot[θ1](x-5Cos[θ1]),{x,-10,10},{y,-10,10},ContourStyle{Black,Dashed}],ParametricPlot[P[θ],{θ,0,θ1},ColorFunction->"BlueGreenYellow"],Graphics[{Black,PointSize[0.018],Point[O1],Text[Style["O",14,Bold],O1,{0,-1.2}],Point[P[θ1]],Text[Style["P",14,Bold],P[θ1],{0,-1.2}],Point[C1[θ1]],Text[Style["C",14,Bold],C1[θ1],{0,-1.2}],Point[A],Text[Style["A",14,Bold],A,{0,-1.2}],Thick,Line[{P[θ1],A}],Line[{O1,C1[θ1]}],Blue,Thick,Circle[O1,r]}]},AspectRatioAutomatic,AxesTrue,AxesOrigin{0,0},PlotRange10],Style["Ellipse",Bold,Large],{{θ1,0.00002,"Value ()"},0.000001,2π,0.1},Delimiter,{{t,3,"Distance from point P to circumference and from point P to point A. "}},ControlPlacementTop
8Cos[θ]
5-3Cos[θ]
8Sin[θ]
5-3Cos[θ]
PC
PA
θ
1
Out[]=

