?

Integral[(1/(1+Exp[-x]))*Log[1/(1+Exp[-x])],x]​
alternate interpretations
related computations
full Wolfram|Alpha results
Assuming "Log" is the natural logarithm
|
Use
the base 10 logarithm
instead
In[10]:=
Integrate[(1/(1 + Exp[-x]))*Log[1/(1 + Exp[-x])], x]
Out[10]=
-
Li
2
(1+
x

)+
1
2
2
log
1
x

+1
+log(-
x

)log
1
x

+1
-log
x

x

+1
log
1
x

+1
+
c
1

​