Sign Up FREE!  Sign In  Classroom Setup  Common Core Alignment  
10222006  #1 
Join Date: Oct 2006
Posts: 822

I'm stuck
Find 2x+5 if x satisfies sqrt(409x)2sqrt(7x)=sqrt(x)
I'm stuck HElP!!! 
10222006  #2 
Join Date: Mar 2005
Posts: 10,609

First, square both sides to remove complex (imaginary) numbers.
Then, solve equation for x. It involves manipulating radicals.
__________________
Do Math and you can do Anything! Last edited by Mr. Hui; 10222006 at 01:48 PM.. 
10222006  #3 
Join Date: Mar 2005
Posts: 10,609

Radicals are expression involving the square root symbol.
__________________
Do Math and you can do Anything! 
10252006  #4 
Join Date: Oct 2006
Posts: 822

I don't know about this...
Is x=1??????
Thanks for the help 
10252006  #5 
Join Date: Oct 2006
Posts: 822

sorry/is the answer to the problem 7
Whoops, didn't read the question.
Is the answer to the problem 7? 
10252006  #6 
Join Date: Mar 2005
Posts: 10,609

No, if you plug in x = 7, you won't get the two sides equal. I will provide you with a complete solution.
__________________
Do Math and you can do Anything! 
10252006  #7 
Join Date: Oct 2006
Posts: 822

I made a mistake
it should be something like 409x+7+x+2sqrt...
__________________
. 
10262006  #8 
Join Date: Mar 2005
Posts: 10,609

As promised, here is the completely worked out solution.
Click to enlarge
__________________
Do Math and you can do Anything! 
10262006  #9 
Guest
Posts: n/a

wtf
wtf dont show that again

10302006  #10 
Guest
Posts: n/a

show what??

Thread Tools  
Display Modes  

