κp
1
=κ1+
μ1
3
κ1+
μ1
3
κp
2
=κ2+
μ2
3
κ2+
μ2
3
μp
1
=μ1
μ1
μp
2
=μ2
μ2
c
1
=1-
c
2
1-
c
2
Ν=2
2
kp=
-1
Ν
∑
r=1
c
r
κp
r
+
μp
1
-
μp
1
-μ1+
1
1-
c
2
κ1+
4μ1
3
+
c
2
κ2+μ1+
μ2
3
kp1=Limit[kp,{κ1∞,κ2∞,μ15,μ230}]